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   To Explore Linear Algebra on the Pythabacus

The Steps Below Generate a Linear Equation and (X), its Solution. See Video Below

STEP1:Click Application, Then Press Enter/Return or Click Check Button.

STEP2:Counting Left From the Rightmost Gold Bead, Left Click a  Gold Bead at a position Greater Than two and Less Than Eight. Click Right Arrow (CRA). This Step Generates (X - C), Which Equals the Gold Beads Against the Right Post.

STEP3:Counting Left From the Rightmost Gold Bead of the Next Group, Left Click a Gold  Beads at any position. CRA. This Step Generates (M), the Gold Beads Displaced to the Middle of the Frame and (Y), Which Equals the Quadrilateral of Brown Beads to the Right and Above the Triangle of Brown Beads Above the Gold Beads.

STEP4:Counting Right From the Leftmost Gold Bead of the Group Against the Right Post, Left Click a Gold Beads at any position. PLA, or Counting Left From the Rightmost Gold Bead of the Middle or Last Group, Left Click a Gold  Bead at any position  CRA. This Step in the First Case Generates a Positive Value for (C) or in the Second Case a Negative 
Value for (C). Click rightmost gold bead and click left arrow button
Hover mouse over gold beads until one bead flashes and beeps. If no bead flashes click rightmost bead again.
StepA: Counting left from the rightmost gold bead left click a bead at a position equal a number that times the number by which (X) is multiplied (M) equals (Y) and CRA until this number of gold beads  rest against the right post. In other words left click the bead you now hover over and CRA.
To convert equation to its inverse, click minus button in top right corner of application.
StepA: If the number in the  second line of the equation is substracted count from the leftmost bead against the right post and left click a gold bead at a position equal the number and CLA to push beads into middle group. Also, push any associated brown beads to the left. If number in second line of equation is added count from the righttmost bead in the middle group and left click a gold bead at a position equal the number and CRA to push beads into rightpost group.
Hover mouse over gold beads until one bead flashes and beeps. 
StepB: Counting left from the rightmost bead remaining against the left post left click a gold bead at a position equal (M) and CRA to push this number  of beads to the right midway toward the beads against the right post . In other words left click the bead you now hover over and CRA. 		StepB: If the number multiplying in the  third line of the equation is positive count from the rightmost bead in the middle to beads against the left post and left click a gold bead at a position equal the number and CRA. If number multiplying in the third line of equation is negative click the rightmost bead and CLA to push group into the middle group, count from the lefttmost bead of this group and left click a gold bead to the right of the position equal the number and CRA to push remainder of group back agaist right post.
Hover mouse over gold beads until one bead flashes and beeps.
StepC: If the sign on the constant on the left side of the equation is negative, then counting left from the rightmost gold bead of the middle group equal (M), count  to a position equal a number that times (M) equals the constant. Left click and CRA until this number of beads rest against the right post. If the sign on the constant on the left side of the equation is positive, then counting right from the leftmost bead of the gold beads against the right post, count  to a position equal a number that times (M) equals the constant. Left click and PLA until all beads to the left rest against the left post. In other words left click the bead you now hover over and proceed according to directions above. The number of beads against the right post will equal the solution (X). Press down arrow to see algebraic solution.		 StepC: If X is positive, X will equal the number of beads in the rectantgles above the middle group and group against the right post.
If X is negative, X will equal the number of beads in the rectantgles above the middle group and group against the right post plus the square of gold beads in the middle group..
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